The 14 Biggest NBA Sneaker Deals Of 2019: Michael Jordan & LeBron James Tops

Unsurprisingly, Michael Jordan tops the list of the biggest NBA sneaker deals for the past fiscal year ending in May 2019, according to Forbes magazine. The Charlotte Hornets owner earned a whopping $130 million through sneaker money, while LeBron James at No. 2 made a big check of $32 million through Nike.

Rounding out the ten five is Kevin Durant ($26 million), Stephen Curry ($20 million), Kobe Bryant ($16 million), James Harden ($14 million), Zion Williamson ($13 million), Dwyane Wade ($12 million), Russell Westbrook ($12 million), and Kyrie Irving ($11 million).

Derrick Rose also made the cut at No. 11 with $11 million, followed by Damian Lillard ( $10 million) and Klay Thompson ($9 million).

These are the 14 biggest NBA sneaker deals of 2019

1. Michael Jordan (Jordan): $130 million
2. LeBron James (Nike): $32 million
3. Kevin Durant (Nike): $26 million
4. Stephen Curry (Under Armour): $20 million
5. Kobe Bryant (Nike): $16 million
6. James Harden (Adidas): $14 million
7. Zion Williamson (Jordan): $13 million
8. Dwyane Wade (Li-Ning): $12 million
9. Russell Westbrook (Jordan): $12 million
10. Kyrie Irving (Nike): $11 million
11. Derrick Rose (Adidas): $11 million
12. Giannis Antetokounmpo (Nike): $10 million
13. Damian Lillard (Adidas): $10 million
14. Klay Thompson (Anta): $9 million

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